I have two lengths of string. Both pieces of string are identical, and each piece of string burns from end to end in exactly one hour.
How do you measure 45 minutes using these pieces of string?
I have two lengths of string. Both pieces of string are identical, and each piece of string burns from end to end in exactly one hour.
How do you measure 45 minutes using these pieces of string?
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Fold one piece of string into quarters, then 45 minutes will have passed once it's burned 3/4 of the way along?
"If at first you don't succeed, spend a lot of money to have a professional do it for you."
My Battlelog
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I have two strings.
I name one 'Fred', the other 'George'
I take fred and light both ends at the same time.
With the thread burning at either end, when the two ends eventually meet, then this means 30 minutes has passed. (The time is halved as it's being burnt on either end.)
I take George, and at the same time as Fred, I burn only /one/ end of George.
30 minutes passes and Fred is gone, I then light the other end of George.
Now George is roughly 50% of its original size, meaning there is roughly 30 minutes left if I leave it as it is.
Imagine if it's easier that George was always at half size.
now I light the opposite end of George, and wait until the string has been burnt completely.
This gives me 45 minutes, as 30 of these minutes was signified by 100% of Fred, and 50% of George (we assume).
100% (1 Hour) + 50% (George's remaining time) is equal to 30 minutes.
30 / 2 = 15, 30 + 15 = 45.
15 = 50% of George.
George may not be 50% in actual size, but 50% of the hour that George contains is gone. This isn't about length, this is about time.
I think I won?
Take that ya one-eyed, bomb-lobbin', cactus eatin', pot bellied, thug fat jigglin-chicken whoopin' big, back-stabbin lob-armed creepy spastic bloody, blind-eyed pashy little twitchy pickle-headed rocke- hoppin, potato-poppin' phony two-faced stealthy mutant bastard!
i7 920@3.8 | GTX280 | HAF 932 | 6GB | Corsair 520W
Hazro 24" | Logitech Illuminated | G500 | Creative 2.0 | Nikon D3100
Googling? You insult my intelligence =/
I used Yahoo actually!
Last edited by Bloo; 6th September 2010 at 09:25 PM.
Take that ya one-eyed, bomb-lobbin', cactus eatin', pot bellied, thug fat jigglin-chicken whoopin' big, back-stabbin lob-armed creepy spastic bloody, blind-eyed pashy little twitchy pickle-headed rocke- hoppin, potato-poppin' phony two-faced stealthy mutant bastard!
you wake up in a rooom
the room has 2 doors leading out, one leads to certain death, the other to certain freedom..
There are 2 men standing in the middle of the room.
One man ALWAYS tells the truth
The other ALWAYS lies.
you are only allowed to ask 1 question. directed at 1 of the men.
what question do you ask, to find out which door to go through?
(note: you want certain freedom)
i am vindictive, faggits!
Damn, that seems really simple but I'm sure there's a catch somewhere.
Assuming that the two men know which door is which, it would appear that you could ask, "Which door leads to certain freedom" to either of them. You take the door the honest man tells you, and not the one the lier tells you.
i7 920@3.8 | GTX280 | HAF 932 | 6GB | Corsair 520W
Hazro 24" | Logitech Illuminated | G500 | Creative 2.0 | Nikon D3100
I ask the man who always tells the truth which door leads to certain freedom.
He tells me the correct answer.
I exit the room.
- I think there's a little more to this riddle than you put?
Take that ya one-eyed, bomb-lobbin', cactus eatin', pot bellied, thug fat jigglin-chicken whoopin' big, back-stabbin lob-armed creepy spastic bloody, blind-eyed pashy little twitchy pickle-headed rocke- hoppin, potato-poppin' phony two-faced stealthy mutant bastard!
i7 920@3.8 | GTX280 | HAF 932 | 6GB | Corsair 520W
Hazro 24" | Logitech Illuminated | G500 | Creative 2.0 | Nikon D3100
The whole point of that story was you dont know who is who but sir nublet re wrote it wrong
i7 920@3.8 | GTX280 | HAF 932 | 6GB | Corsair 520W
Hazro 24" | Logitech Illuminated | G500 | Creative 2.0 | Nikon D3100
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