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Thread: Riddle me this

  1. #1
    Yellow and mellow Calneon's Avatar
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    Riddle me this

    I have two lengths of string. Both pieces of string are identical, and each piece of string burns from end to end in exactly one hour.

    How do you measure 45 minutes using these pieces of string?

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    Community Manager Chazlene's Avatar
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    Re: Riddle me this

    Fold one piece of string into quarters, then 45 minutes will have passed once it's burned 3/4 of the way along?
    "If at first you don't succeed, spend a lot of money to have a professional do it for you."


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  3. #3
    Yellow and mellow Calneon's Avatar
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    Re: Riddle me this

    Quote Originally Posted by Chazlene View Post
    Fold one piece of string into quarters, then 45 minutes will have passed once it's burned 3/4 of the way along?
    You assume that the string burns evenly through the entire length of the string.

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    ATK Member Mr.Big's Avatar
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    Re: Riddle me this

    you go on google and try 'n find a solution
    Quote Originally Posted by Phantom View Post
    Being a pirate is not illegal VoX, you just have to be a bit mad to do it. I for one love Mr.Big for who he is.
    Quote Originally Posted by Oricalcos View Post
    And no Mr. Big, I will not buy every single module in T2 form just because I have exuberant amounts of liquid capital
    Quote Originally Posted by Target View Post
    @ Vox its not worth buying Ass Creed 2 its more of the same just "Mr Big" it and then buy BC2

  5. #5

    Re: Riddle me this

    Sure is XKCD in here

  6. #6
    ATK Member ez64's Avatar
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    Re: Riddle me this

    Quote Originally Posted by Calneon View Post
    I have two lengths of string. Both pieces of string are identical, and each piece of string burns from end to end in exactly one hour.

    How do you measure 45 minutes using these pieces of string?
    numb/encore?

  7. #7
    ATK Member Vicious Horizon's Avatar
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    Re: Riddle me this

    I have two strings.

    I name one 'Fred', the other 'George'

    I take fred and light both ends at the same time.

    With the thread burning at either end, when the two ends eventually meet, then this means 30 minutes has passed. (The time is halved as it's being burnt on either end.)

    I take George, and at the same time as Fred, I burn only /one/ end of George.

    30 minutes passes and Fred is gone, I then light the other end of George.

    Now George is roughly 50% of its original size, meaning there is roughly 30 minutes left if I leave it as it is.

    Imagine if it's easier that George was always at half size.

    now I light the opposite end of George, and wait until the string has been burnt completely.

    This gives me 45 minutes, as 30 of these minutes was signified by 100% of Fred, and 50% of George (we assume).

    100% (1 Hour) + 50% (George's remaining time) is equal to 30 minutes.

    30 / 2 = 15, 30 + 15 = 45.

    15 = 50% of George.



    George may not be 50% in actual size, but 50% of the hour that George contains is gone. This isn't about length, this is about time.





    I think I won?
    Take that ya one-eyed, bomb-lobbin', cactus eatin', pot bellied, thug fat jigglin-chicken whoopin' big, back-stabbin lob-armed creepy spastic bloody, blind-eyed pashy little twitchy pickle-headed rocke- hoppin, potato-poppin' phony two-faced stealthy mutant bastard!


  8. #8
    Yellow and mellow Calneon's Avatar
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    Re: Riddle me this

    Quote Originally Posted by Vicious Horizon View Post
    I have two strings.

    I name one 'Fred', the other 'George'

    I take fred and light both ends at the same time.

    With the thread burning at either end, when the two ends eventually meet, then this means 30 minutes has passed. (The time is halved as it's being burnt on either end.)

    I take George, and at the same time as Fred, I burn only /one/ end of George.

    30 minutes passes and Fred is gone, I then light the other end of George.

    Now George is roughly 50% of its original size, meaning there is roughly 30 minutes left if I leave it as it is.

    Imagine if it's easier that George was always at half size.

    now I light the opposite end of George, and wait until the string has been burnt completely.

    This gives me 45 minutes, as 30 of these minutes was signified by 100% of Fred, and 50% of George (we assume).

    100% (1 Hour) + 50% (George's remaining time) is equal to 30 minutes.

    30 / 2 = 15, 30 + 15 = 45.

    15 = 50% of George.



    George may not be 50% in actual size, but 50% of the hour that George contains is gone. This isn't about length, this is about time.





    I think I won?
    You won the googling contest yeah.

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  9. #9
    ATK Member Vicious Horizon's Avatar
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    Re: Riddle me this

    Googling? You insult my intelligence =/


    I used Yahoo actually!
    Last edited by Bloo; 6th September 2010 at 09:25 PM.
    Take that ya one-eyed, bomb-lobbin', cactus eatin', pot bellied, thug fat jigglin-chicken whoopin' big, back-stabbin lob-armed creepy spastic bloody, blind-eyed pashy little twitchy pickle-headed rocke- hoppin, potato-poppin' phony two-faced stealthy mutant bastard!


  10. #10

    Re: Riddle me this

    you wake up in a rooom

    the room has 2 doors leading out, one leads to certain death, the other to certain freedom..

    There are 2 men standing in the middle of the room.
    One man ALWAYS tells the truth
    The other ALWAYS lies.

    you are only allowed to ask 1 question. directed at 1 of the men.

    what question do you ask, to find out which door to go through?
    (note: you want certain freedom)
    i am vindictive, faggits!



  11. #11
    Yellow and mellow Calneon's Avatar
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    Re: Riddle me this

    Quote Originally Posted by Setsoru View Post
    you wake up in a rooom

    the room has 2 doors leading out, one leads to certain death, the other to certain freedom..

    There are 2 men standing in the middle of the room.
    One man ALWAYS tells the truth
    The other ALWAYS lies.

    you are only allowed to ask 1 question. directed at 1 of the men.

    what question do you ask, to find out which door to go through?
    (note: you want certain freedom)
    Damn, that seems really simple but I'm sure there's a catch somewhere.

    Assuming that the two men know which door is which, it would appear that you could ask, "Which door leads to certain freedom" to either of them. You take the door the honest man tells you, and not the one the lier tells you.

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  12. #12
    ATK Member Vicious Horizon's Avatar
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    Re: Riddle me this

    I ask the man who always tells the truth which door leads to certain freedom.

    He tells me the correct answer.

    I exit the room.


    - I think there's a little more to this riddle than you put?
    Take that ya one-eyed, bomb-lobbin', cactus eatin', pot bellied, thug fat jigglin-chicken whoopin' big, back-stabbin lob-armed creepy spastic bloody, blind-eyed pashy little twitchy pickle-headed rocke- hoppin, potato-poppin' phony two-faced stealthy mutant bastard!


  13. #13
    Yellow and mellow Calneon's Avatar
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    Re: Riddle me this

    Quote Originally Posted by Vicious Horizon View Post
    I ask the man who always tells the truth which door leads to certain freedom.

    He tells me the correct answer.

    I exit the room.


    - I think there's a little more to this riddle than you put?
    I've read through it again and I can't find a hole in it.

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  14. #14
    ATK Member ez64's Avatar
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    Re: Riddle me this

    The whole point of that story was you dont know who is who but sir nublet re wrote it wrong

  15. #15
    Yellow and mellow Calneon's Avatar
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    Re: Riddle me this

    Quote Originally Posted by ez64 View Post
    The whole point of that story was you dont know who is who but sir nublet re wrote it wrong
    Well then it's random and not a riddle...

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